Designing exercise and solution for Basic Algebra. [M1]
EXERCISE: BIDMAS
11)2x5+7 3) 10 -2x5 5) (4-3)x(10-7) 7) (55-5)➗5
=17 =0 1 x 3 50➗5
=3
=10
2) (2+7)x3 4)14-6+9 6)36➗4+5 8)(37-3)➗(12-8)
=27 =17 9+5 34 ➗ 4
=14
=8
Example I:
a a)
Find a
when
1)
a=4 b) a=8
a=3a+7 a=3a+4
a=3(4)+7 a=3(8)+4
a=12+7 a=24+4
a=19 a=28
Example ll:
l) 5+3b ll) 2b-10
5+3(6) 2(6)-10
5+3(6) 2(6)-10
5+18 12-10
=23 =2
i)K=7 ii) k=3
h=5(12-7) h=5(12-3)
h=5(5) h=5(9)
h=25 h=45
c) use the rule a=6-b
to work out a when:
3
i)b=6 ii) b= 15
6-6 6-15
3 3
2-2 2-5
1 1
= 0 =-3
1 1
= 0 =-3
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